函数f(x)=sin(3x 4 3π 2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 11:11:39
对f(x)作图,你可以很容易的发现,在0到π范围内,是sin(3x)的叠加,在π到2π范围内,sin(3x)为负,|sin(3x)|是正,它们抵消掉了,所以这个范围内f(x)是等于0的.后面的以此类推
1、由于函数g(x)=sin(2(x-a)+π/3)为偶函数,所以g(x)的图像关于y轴对称,即函数g(x)当x=0时取得最值,所以g(0)=±1,解得sin(π/3-2a)=±1,sin(2a-π/
(1)f(x)=√3(1-cos2x)-1/2sin2x+√3/2cos2x=√3-1/2sin2x-√3/2cos2x=√3-sin(2x+π/3)∴最小正周期T=2π/2=π单调增区间:π/2+2
f(x)=sinx-sin(x-π3)=12sinx+32cosx=sin(x+π3)∴函数f(x)=sinx-sin(x-π3)的最大值为1故答案为:1
f(x)=sin²(x)+(√3)sin(x)cos(x)+2cos²(x)=3/2+√3/2sin2x+1/2cos2x=3/2+sin(2x+π/6)函数f(x)的最小正周期T
你的题目是这样的吗已知函数f(X)=2sin(ax-π/6)sin(ax+π/3)(其中a为正常数,x∈R)的最小正周期为π(1)求a的值(2)在△ABC中,若A<B,且f(A)=f(B)=1/2,求
f'(x)=2sin(2x+兀/3)(sin(2x+兀/3))'=2sin(2x+兀/3)cos(2x+兀/3)(2x+兀/3)'=2sin(4x+2兀/3)
1)由三角函数和差化积公式:f(x)=2sin(x+x+π/3)/2cos(x-x-π/3)/2=2sin(x+π/6)cos(π/6)=√3sin(x+π/6)f(x)的最小值为-√3.当x+π/6
y=sinx^2+根3sinxcosx+2cosx^2=-1/2(1-2sinx^2)+1/2根3*2sinxcosx+2cosx^2-1+3/2=-1/2cos2x+二分之根3倍sin2x+cos2
f(x)=2√3sin²x-sin(2x-π/3)=√3-√3cos2x-1/2sin2x+√3/2cos2x=√3-(1/2sin2x+√3/2cos2x)=√3-sin(2x+π/3)T
fx=2cosx(0.5sinx+根号3/2cosx)-根号3sin*2x+sinxcosx=2sinxcosx+根号3(cos*2x-sin*2x)=sin2x+根号3cos2x=2sin(2x+派
f(x)=cos(x-π/3)-sin(π/2-x)=(1/2)cosx+(√3/2)sinx-cosx=(√3/2)sinx-(1/2)cosx=sin(x-π/6),它的最小值=-1.
(1)F(X)=√3sin2x+2sin²x=√3sin2x+1-cos2x=2(√3/2sin2x-1/2cos2x)+1=2sin(2x-π/6)+1F(x)的最小正周期T=2π/2=π
解x+70=x+10+60f(x)=3sin(x+10)+5sin(x+10)*cos60+5*sin60*cos(x+10)=(11/2)sin(x+10)+5*cos(x+10)3^0.5=7*s
f(x)=sin^2x+2√3sinxcosx+sin(x+π/4)sin(x-π/4)=(1-cos2x)/2+√3sin2x+(1/2)2sin(x-π/4)cos(x-π/4)=2-2cos2x
f(25π/6)=f(π/6)3sin²x+sinxcosx=3sin²x+0.5sin2xf(x)=--根号下3sin²x+0.5sin2x然后根据函数的单调性就可求出
(1)已知函数f(x)=-(√3)sin²x+sinxcosx,求f(25π/6).f(x)=-(√3)sin²x+sinxcosx=(√3/2)(cos2x-1)+(1/2)si
答:1)f(x)=√3cos²x+sinxcosx-√3/2=(√3/2)(2cos²x-1)+(1/2)*2sinxcosx=(√3/2)cos2x+(1/2)sin2x=sin
f(x)=sin^2x+2√3sinxcosx+3cos^2x=1+√3sin2x+2cos^2x-1+1=√3sin2x+cos2x+2=2(sin2x*√3/2+cos2x*1/2)+2=2sin