如图,已知ABⅡCD,OA=OD,AE=DF,求证:BEⅡCF.
如图,已知ABⅡCD,OA=OD,AE=DF,求证:BEⅡCF.
如图AB=CD,BE=CF,AE=DF求证OA=OD
已知BC,EF交点O,AB//CD,OA=OD,AE=DF,求证BE//CF
如图,已知AB//CD.OA=OD,点F.D.O.A.E在同一条线上,AE=DF,求证,EB//CF
如图,已知AB‖CD,BC/EF相交于点O,OA=OD,AE=DF,求证:EB‖CF
如图,已知AB‖CD,OA=OD,AE=DF,求证①△ABE≡△DCF②EB‖CF
如图,已知AB‖CD,OA=OD,延长OA到E,延长OD到F,使AE=DF.求证△OEB全等于△OFC
如图,AB∥CD,OA=OD,点F、D、O、A、E在同一直线上,AE=DF,求证:EB∥CF.
如图所示,已知AB=CD,BE=DF,AE=CF,求证:OA=OC,OE=OF
如图所示,已知AB平行CD,OA=OD,BC过O 点,E,F在直线AOD上且AE=DF.求证EB平行CF
已知如图,E.F在BD上,且AB=CD,BF=DE,AE=CF,求证:OA=OC.OB=OD
已知:如图,AB=CD,BC=DA,AE=CF.求证:DF=DE