设f(n)=1/(n+1)+1/(n+2)+……+1/(2n) (n∈N新),那么f(n+1)-f(n)等于(1/(2n
设f(n)=1/(n+1)+1/(n+2)+……+1/(2n) (n∈N新),那么f(n+1)-f(n)等于(1/(2n
设f(n)=1n+1+1n+2+1n+3+…+13n(n∈N*),则f(n+1)-f(n)=( )
如果f(n)=1/(n+1)+1/(n+2)+```1/2n (n属于N*) 那么f(n+1)-f(n)=
f(n)=1/(n+1)+1/(n+2)+…+1/(2n-1)+1/(2n) (n≥2,n∈N*)
设f(n)=1/(n+1)+1/(n+2)+...+1/2n,则f(n+1)-f(n)等于()
设f(n)=1n+1+1n+2+…+12n(n∈N),则f(n+1)-f(n)= ___ .
设函数f(x)满足f(n+1)={2f(n)+n}/2,(n∈正整数),且f(1)=2,那么f(20)=?
求证f(n+1)*f(n-1)-f(n)*f(n) = (-1)^n,f(n)是费波纳茨数列
设定义在N*上的函数f(n)=n(n为奇数);f(n)=f(n/2)(n为偶数),an=f(1)+f(2)+f(3)+·
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
设函数f(x)满足f(n+1)=(2f(n)+n)/2 n为正整数,则f(20)为?
f(n+1)—f(n)=2n+2,则f(n)=?