main() int a=1; printf("%d\n",(a=a+2,a+3));输出结果为6. 咋么理解?
main() int a=1; printf("%d\n",(a=a+2,a+3));输出结果为6. 咋么理解?
求下列程序输出结果#includevoid main(){int a=3;printf("%d\n",(a+=a-=a*
求输出结果?main() int a=1,b=2;a=a+b;b=a-b;a=a-b;printf(“%d,%d\n”,
main() {int a[10]={1,2,3,4,5}; printf("%d\n",a[6]);}输出的结果是啥,
以下程序的输出结果是( ).main( ){ int a=011;printf("%d\n",++a);} A) 12
若定义:int a=511,*b=&a;,则printf("%d\n",*b);的输出结果为 ( ).
4.下列程序的输出结果是___B____.main() { int a = 011; printf( "%d\n",++
以下程序运行后的输出结果是?main(){int a=1,b=2,c=3;if(c=a)printf("%d\n",c)
以下程序的输出结果是______. main() { int a=0; a+=(a=8); printf("%d\n",
#include"stdio.h"main(){int a=-1 printf("%d,%u,%o,%x\n",a,a,
main(){int a=1,i=a+1;do{a++;}while(!~i++>3);printf("%d\n",a)
main() { int a=2;a%=4-1; printf("\n%d,",a); a+=a*=a-=a*=3; p