log(a-1) (2x-1)-log(a-1)(x-1)>0
log a(1/2次方) x等于2log a
对数的运算问题-log a 1/x=-(log a 1-log a x)=log a x
log(a-1) (2x-1)-log(a-1)(x-1)>0
解方程[log(a)(x-1)]-[log(a)(2x-3)]=log(a)(1/3-x),(a>0,且a≠1).
[log (底数为a) x]=[1\2log (底数为a) b ] - [ log (底数为a)c]求X
f(x)=|log(a)(x)-1|+|2log(a)(x)|,求使f(x)<2的x范围,
设log(a)(x+y)=根号三,log(a)x=1,求log(a)y
matlab求积分syms x; a=int(1/(1-x^2)*(log(1+x)-log(1-x)); a
已知0<a<1,x=log a 根号2+log a 根号3
【高二数学】设a>0且a≠1,函数f(x)=log a (x²-2x+3)有最小值,则不等式log a (x-
对数函数的问题.log a x 与log (a^-1) x的关系.
已知log(1-2a)2x <log(3a-1)x求a的取值范围