x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy

来源：学生作业帮编辑：搜狗做题网作业帮分类：数学作业时间：2024/05/10 19:27:32

(x²-4y²)/(x²+2xy+y²)÷(x+2y)/(2x²+2xy)
=(x-2y)(x+2y)/(x+y)²÷(x+2y)/(2x²+2xy)
=(x-2y)(x+2y)/(x+y)²*(2x²+2xy)/(x+2y)
=(x-2y)/(x+y)²*(2x²+2xy)
=(x-2y)/(x+y)²*2x(x+y)
=(x-2y)/(x+y)*2x
=2x(x-2y)/(x+y)

x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 1-x²+2xy-y² 计算:(1).(-2xy²)*(3x²y)² 先化简,再求值：3xy²(-x²y+2x³y²)-4xy(-xy²)· 分式的除法运算x²－4y²/x²+y²+2xy÷2y+x/x²+xy 因式分解 x²-3xy+2y²+x-2 (x+2y)²-x²-2xy |x+2y+3|+(2x+y)²=0求x²-xy+y² 已知x/y=3,求x²+2xy-3y²/x²-2xy+y² x/y=2,求分式x²-xy+3y²/x²+xy+6y² 已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+