(1)x4-12x+323

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(1)x4-12x+323
(2)x4+7x3+14x2+7x+1

(1)x4-12x+323
=(x^4+36x^2+324)-(36x^2+12x+1)
=(x^2+18)^2-(6x+1)^2
=(x^2+6x+19)(x^2-6x+17)
(2) x4+7x3+14x2+7x+1
=(x^4+2x^2+1)+(7x^3+21x^2+7x)-9x^2
=(x^2+1)^2-(3x)^2+7x(x^2+3x+1)
=(x^2+3x+1)(x^2-3x+1)+7x(x^2+3x+1)
=(x^2+3x+1)(x^2+4x+1)

(1)x4-12x+323 x4-47x²+1 已知x2+x+1=0 求x4+1/x4 X5-X4+X3+X2+X+1因式分解 x5-x4+x3-x2+x-1因式分解 3分之5x4+4分之x-1等于2-12分之5x-5 如果x平方-3x+1=0,求x4次方+x4次方分之一的值. x平方-4x+1=0 求x4次方+x4次方分之一若X2+1除以X=5,求X4+X2+1除以X4-X2+1 已知x2+3x+1=0,求x4+1/x4的值. 已知x2+x+1=0,求x4+1/x4的值 -3x4+12x(1/3-5/2)简便方法计算