高一数学急!已知f(a)=sin^2(π-α)·cos(2π-α)·tan(-π+α)/sin(-π+α)·tan(-α
高一数学急!已知f(a)=sin^2(π-α)·cos(2π-α)·tan(-π+α)/sin(-π+α)·tan(-α
已知α是第三象限角,f(α)=[sin(π-a)cos(2π-a)tan(1.5π-a)tan(-a-π)]/sin(-
高一数学月考题.已知sin[π+α]=-1/2,求sinα,cosα,tanα的值
②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π
已知α为第三象限角,且f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)tan(2π-α)
已知f(α)=sin(π-α)cos(2π-α)tan(π-α)/-tan(-π-α)sin(-π-α),若α是第三象限
已知f(α)=sin(π-α)cos(2π-α)tan(-α+3π/2)tan(-α-π) /sin(-π-α).(1)
已知sin a=2cos a 计算⑴(sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)
有关三角函数的题已知f(α)=sin(π-α)cos(2π-α)tan(-α+π)/-tan(-α-π)sin(-π-α
已知α是第三象限角,且f(α)=[sin(π+α)cos(2π-α)tan(-α+3π/2)tan(-α-π)]/sin
已知f=[sin(π-α)cos(2π-α)tan(-π-α)]/sin(-π-α),⑴化简f(a)、⑵若α是第三象限,
高一数学三角函数部分.已知tanα=2 求4sinα-2cosα/5sinα+3cosα的值.5sin^α+...