搜狗做题网（2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)
![（2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)](/uploads/image/z/459994-58-4.jpg?t=%EF%BC%882sin%5E2a%2Bsin2a%29%2F%281%2Btana%29+%E6%95%B4%E7%90%86+%3D%5B2sina%28sina%2Bcosa%29%5D%2F%5B%28sina%2Bcosa%29)
（2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)
求证1+sina-cosa/1+sina+cosa=tana/2
已知tana=2,求值:(1)cosa+sina/cosa-sina
已知tana=3,求①sina+cosa/2sina-cosa ②sin²a+sina·cosa+3cos&#
[(sina+cosa)^2-(sina-cosa)^2]/[tana-sina*cosa]
已知1+tanA/1-tanA=-3,求3sinA*sinA-sin2A+2cosA*cosA的值
证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
求证：1+sina+cosa/1+sina-cosa+1-cosa+sina/1+cosa+sina=2/sina
函数y=sinA+cosA-4sinAcosA+1,且2sin^A+sin2A/1+tanA=k,π/4
tana=2,则sina+cosa/2sina-cosa=
tanA=2,求sinA+cosA/sinA-cosA=
2(sina+cosa)=sina-cosa,求tana