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x+y=1,xy=-1/2,求x(x+y)(x-y)-x(x+y)2

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x+y=1,xy=-1/2,求x(x+y)(x-y)-x(x+y)2
x+y=1,xy=-1/2,求x(x+y)(x-y)-x(x+y)2
x(x+y)(x-y)-x(x+y)2 =x(x+y)[(x-y)-(x+y)]
=x(x+y)(-2y)=-2xy(x+y)
=-2×(-1/2)×1
=1
再问: 18p3q3-2pq
再答: 7(x-1)3-14(x-1)2+7(x-1)=7(x-1)[﹙x-1﹚²-2﹙x-1﹚+1]=7﹙x-1﹚[﹙x-1﹚-1]² =7﹙x-1﹚﹙x-2﹚²