搜狗做题网谁能告诉我和差化积积化和查的公式
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：数学作业 时间：2024/05/04 07:35:51
谁能告诉我和差化积积化和查的公式
sinA + sinB = 2*sin[(A+B)/2]*cos[(A-B)/2]
sinA - sinB = 2*sin[(A-B)/2]*cos[(A+B)/2]
cosA + cosB = 2*cos[(A+B)/2]*cos[(A-B)/2]
cosA - cosB = -2*sin[(A+B)/2]*sin[(A-B)/2] .注意负号
sin(A + B) = sinAcosB + cosAsinB
sin(A - B) = sinAcosB - cosAsinB
coa(A + B) = cosAcosB - sinAsinB
coa(A - B) = cosAcosB + sinAsinB
sin2A = 2sinAcosA
cos2A = (cosA)^2 - (sinA)^2 = 2(cosA)^2 - 1 = 1 - 2(sinA)^2
(cosA)^2 = (1 + cos2A)/2
(sinA)^2 = (1 - cos2A)/2
累死了,打字啊,哈哈哈.
sinA - sinB = 2*sin[(A-B)/2]*cos[(A+B)/2]
cosA + cosB = 2*cos[(A+B)/2]*cos[(A-B)/2]
cosA - cosB = -2*sin[(A+B)/2]*sin[(A-B)/2] .注意负号
sin(A + B) = sinAcosB + cosAsinB
sin(A - B) = sinAcosB - cosAsinB
coa(A + B) = cosAcosB - sinAsinB
coa(A - B) = cosAcosB + sinAsinB
sin2A = 2sinAcosA
cos2A = (cosA)^2 - (sinA)^2 = 2(cosA)^2 - 1 = 1 - 2(sinA)^2
(cosA)^2 = (1 + cos2A)/2
(sinA)^2 = (1 - cos2A)/2
累死了,打字啊,哈哈哈.