求多项式7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3+10,x=12/13,小马虎说这

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求多项式7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3+10,x=12/13,小马虎说这道题没有给出y的值
无法求多项式的值,他说的对吗?为什么?

答案是10 所有的多项式都可以消掉到最后只剩下了10
7x^3-10x^3=-3x^3
-6x^3y+6x^3y=0 直接消掉
+3x^2y-3x^2y=0直接消掉
3x^3和第二行剩的那个 -3x^3 也可以消掉
整个等式就剩下了10了所以答案是10

求多项式7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3+10,x=12/13,小马虎说这因式分解3x^2(x-y)+6x(y-x) 已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 小杰同学在求代数式7X^3-6X^3Y+3X^2Y+3X^3+6X^3Y-3X^2Y-10X^3的值时不小心抄错了X、Y 2(y-x)的平方-7(x-y)+6(x-y)-3(y-x)的平方计算：(x-y)^7÷(y-x)^6+(-x-y)^3÷(x+y)^2