return;顺序表原长度为%d\n",n);grade=score>=90?'A':(score>=60?'B':'C
return;顺序表原长度为%d\n",n);grade=score>=90?'A':(score>=60?'B':'C
else if(score>=90&&score
pcmark score:n/a cpu score:5587 memory score:3216 graphicsco
float score; if ( int(score)-score!=0 ) ...这样输入提示错误我想判断score
int score = 60; if(x>100&&y>500) score=score+1; if(x>=1000||
#includefloat max=0,min=0;float average(float score[],int n)
a=b=c=1; a+=b*=c%=a+b+c; printf("%d,%d,%d\n",a,b,c) 计算顺序
“score
score
score a
已知abcd为实数,M=4(a-b)(c-d)N=(a-b)(c-b) (d-a)(c-b) (c-d)(c-b) (a
#include int main(void) { int n,i,grade,A=0,B=0,C=0,D=0,E=0;