int a[3][5]={{1,2},{6,4},{3,4,5}}; int (*p)[5] = a; 求*(*p+1)
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
int a[3][5]={{1,2},{6,4},{3,4,5}}; int (*p)[5] = a; 求*(*p+1)
{ int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin
int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p
int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**(p+1)-*(*p+1)的
int a[ ][3]={1,2,3,4,5,6,7,8,9,10,11,12};int*p=a;求 *(*(a+2)+
有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5
已知static int a[]={5,4,3,2,1},*p[]={a+3,a+2,a+1,a},**q=p;求*(p
int a[]={1,3,5,7}; int*p[3]=(a+2,a+1,a); int **q=p; printf("
#include "stdio.h" main() { int a []={1,2,3,4,5},*p;p=a;*(p+
C语言问题:int *p; int a[] = {1,2,3,4,5,6}; *++p += 1; 这句话怎么理解.麻烦
c语言int a[ ]=(1,2,3,4,5,6) *P=a,什么意思,*P=1?