搜狗做题网一道分式数学题,1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：数学作业 时间：2024/06/22 18:18:16
一道分式数学题,
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)=?
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)=?
∵1/a(a+1)=1/a -1/(a+1)
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)
∴原式=1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+..-1/(a+2004)+1/(a+2004)-1/(a+2005)
=1-1/(a+2005)
=(a+2004)/(a+2005)
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)
∴原式=1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+..-1/(a+2004)+1/(a+2004)-1/(a+2005)
=1-1/(a+2005)
=(a+2004)/(a+2005)
一道分式数学题,1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2
一道分式数学题[1/a-2 + a²-1/(a+2)(a-1)] / (a/a+2)²化简求值,其中
把分式a/a^2+a-2,a-1/a^2+3a+2,1/1-a^2通分
(a 1)(a 2)(a 3)(a
问一道数学题-(a^3-a^2)+(a-1)=-a^3-()
一道八年级数学分式题已知代数式：A=1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+……+1/(2
先化简分式(a^2-9)/(a^2+6a+9)+（a-3）/(a^2+3a)-(a-a^2)/(a-1)然后在0,1,2
a(a-1)(a-2)(a-3)(a-4)因式分解
一道数学题：已知A=2a-2a B=-3a+2 求：(1)2A-2B (2)2A-[B-(2B+A)]
数学题一道：化简a²+2a-1=0
要使分式a^2-4/1+(1+3a/2a)有意义,则a=?
分式不等式的题,1){（a^2+2a-2）/（3+2a-a^2)}