3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
{2x+y=1,5x+2y=3,加减消元法,求过程
x+y/2+x-y/3=6,4(x+y)-5(x-y)=2用加减消元法解方程组
用加减消元法解 3x+2y=22 2x-3y=40
用加减消元法解方程组{2x+3y=-2 3x-2y=10
解方程组{5x-3y=2 2x-3y=-10 加减消元法.
用加减消元法解方程组{3x+2y=5 2x-3y=8
用加减消元法解方程组2x+y=18,3x-2y=13
2x=-3y=4x-2-y+10,用加减消元法解方程组
5x-3y=2,4y+2x=6用加减消元法
用加减消元法解方程组{4x-5y=5,2x+3y=-25
用加减消元法解方程组 3(x-1)=y+5 2(y+1)=x+1