dy/dx 3x^2+4y^3-2x-5y+1=0
dy/dx 3x^2+4y^3-2x-5y+1=0
dy/dx-2y/(1+x)=(x+1)^3
dy/dx=2y/x+3x/2y
从(dx)/(dy)=1/y '导出:(d^2x)/(dy^2)=-y''/(y')^3
2*x*y^2(dy/dx)- x^3(dy/dx)=2y^3
求解一道微分方程题x*y^3*dy+(y^4-x^2)*dx=0
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3 题目中关于d[1/y']/dx}*[dx/dy
dy/dx=(x^4+y^3)/xy^2
x^2+xy+y^3=1,求dy/dx
微分方程 dy/dx=(e^y+3x)/x^2
y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
求dy/dx=(x-y+5)/(x+y-2)