(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23
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(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=______.
设0.12+0.23=x,0.12+0.23+0.34=y.
则:(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
=(1+x)y-(1+y)x,
=y+xy-x-xy,
=y-x,
=(0.12+0.23+0.34)-(0.12+0.23),
=0.12-0.12+0.23-0.23+0.34,
=0.34.
故答案为:0.34.
则:(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
=(1+x)y-(1+y)x,
=y+xy-x-xy,
=y-x,
=(0.12+0.23+0.34)-(0.12+0.23),
=0.12-0.12+0.23-0.23+0.34,
=0.34.
故答案为:0.34.
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23
简便运算(1+0.12+0.23)X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.2
求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.
计算.要简便 (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.
(0.12+0.23+0.34)*(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)这是题目,
(1+0.23+0.34)×(0.23+0.34+0.56)-(1+0.23+0.34+0.56)×(0.23+0.34
(1+0.23+0.34)×(0.23+0.34+0.65)-(1+0.23+0.34+0.65)×(0.23+0.34
(1+0.23+0.34)*(0.23+034+0.56)-(1+0.23+0.34+0.56)*(0.23+0.34)
计算:(1+0.23+0.34)*(0.2903+0.34+0.56)-(1+0.23+0.34+0.56)*(0.23
0.12+0.23+0.34+0.45+0.56+0.67+0.78+0.89=?
简便运算;0.12+0.23+0.34+……+0.89=
0.01+0.12+0.23+0.34+0.78+0.89等于多少?(小数部分末尾的数字都是循环的)