suppose a roller coaster passes point 1 with a speed of 1.7m

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suppose a roller coaster passes point 1 with a speed of 1.7m/s.if the average force of friction is equal to one -fifth of its weight,with what speed will it reach point this distance traveled is 45m.h1=35 h2=15 h3=28
2explain how might be possible for a moving object to possess,and simultaneously not possess,kinetic energy
用英文答。

重力与摩擦力所做的功等于动能的增量
mgh1-mg*1/15*s=1/2mv^2-1/2mv0^2
v2=[2(1/2mv^2+mgh1-mg*1/15*s)/m]^0.5
=[2(1/2x1.7x1.7+10x35-10x1/15x45)]^0.5
=25.4m/s
It will reach point 2 with a speed of 25.4m/s
The 2rd question I do not know.
再问：是1/5 不是1／15
再答： v2=[2(1/2mv^2+mgh1-mg*1/5*s)/m]^0.5 =[2(1/2x1.7x1.7+10x35-10x1/5x45)]^0.5 =22.9m/s It will reach point 2 with a speed of 22.9m/s

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