In Fig.13-41,a particle of mass m1 = 0.24 kg is a distance d
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In Fig.13-41,a particle of mass m1 = 0.24 kg is a distance d = 38 cm from one end of a uniform rod with length L = 6.7 m and mass M = 3.3 kg.What is the magnitude of the gravitational force on the particle from the rod?
是在考你基本的积分
假设杆的质量线密度是p=M/L
对于图中的线元dr,它的质量dm=p×dr
粒子受到的引力是
dF=Gm1×dm/r^2
积分从d到d+L
最后得到总的引力
F=Gm1×M/(d×(d+L))
假设杆的质量线密度是p=M/L
对于图中的线元dr,它的质量dm=p×dr
粒子受到的引力是
dF=Gm1×dm/r^2
积分从d到d+L
最后得到总的引力
F=Gm1×M/(d×(d+L))
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