C#编写一个函数用来求任意多个整数中的最大数

intfun(intn){inta=n,b=0;while(a>0){b=b*10;b=b+a%10;a=a/10;}printf("%d",b);getch();return0;}或者把后三行删掉,

#include"stdio.h"voidmain(){inta,b,i;intsum=0;printf("Inputstartyear:");scanf("%d",&a);printf("

intcount=0;for(inti=1;i

#includeintsum(intn){ints=0;while(n){s+=n%10;n/=10;}returns;}intmain(void){ints=0;for(int

这个简单：#includeusingnamespacestd;intHe(intx,inty){intz;z=x+y;returnz;}intCha(intx,inty){intz;z=x-y;ret

#include<stdio.h>int getmax(int a,int b){      re

SOEASY

usingSystem.Text;namespaceTiXing{classProgram{/**程序名称：控制台求梯形面积的C#程序*注意：该程序未进行错误判断,要求用户输入的参数必须符合规则.*输

#includemain(){intn;printf("Pleaseenteranumber:");scanf("%d",&n);if(n%2==0)printf("Thenumber%dis偶数\n

intx=4;for(inti=0;iif(iinty=1;for(intj=0;jif(y>0){if(jConsole.Write("");}if(j>=(x-i-1)&&jConsole.Wri

诠释文本（整数K）{整数总和=I;INTI=0;就（i=1;I

如果是要求前N个偶数之和：#includeusingnamespacestd;longFunctionadd(intn){longsum=0;for(inti=0;i

importjava.util.Scanner;publicclassOushu{Oushu(){try{System.out.println("请输入n值");Scannerin=newScanne

A = rand(5,6)a = sort(A(:));minv = a(1);[r,c] = find(A==minv

#include#include#defineA12#defineB9voidpaixu(intm[],intshu);main(){inta[A];intb[B];inti;doublea1,b1;

packagetest;publicclassTest{publicstaticvoidmain(Stringargs[]){System.out.println(getSum(123));}publ

voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}

#includeusingnamespacestd;voidmain(){inta=0,b=0;cin>>a>>b;cout

#includevoidmain(){inta,b,sum=0;printf("请输入两个整数：");//将两个改成n个就好了scanf("%d%d",&a,&b);sum=a+b;printf("%

好别扭,还是叫静态方法好一点,面向对象里面一般叫方法,不叫函数.静态方法：属于类,使用class.method()调用,在程序运行之初就会被装入内存,在程序的运行期间一直存在.非静态方法：属于类的对象