若函数y f x 是由方程arctany x=ln
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/06 15:29:45
方程两边同时求x对y的导:y+xdy/dx+1/x+2ydy/dx=0,dy/dx=-(y+1/x)/(x+2y),dy=-(y+1/x)dx/(x+2y)
d2y/dx2是求y对x求2次导dy/dx是1次导,因为是参数方程,所以x,y要分别对t求导dy/dx=(dy/dt)/(dx/dt)=G'(t)/F'(t)2次导就再对x求导一次,这个d/dx[G'
令F=e^z-xyzF对x的偏导数为Fx=-yzF对z的偏导数为Fz=e^z-xy由偏导公式z对x的偏导=-Fx/Fz=yz/(e^z-xy)
arctanx表示一个角度,a1=arctanx1;a2=arctanx2;tana1=x1;tana2=x2;tan(arctanx1+arctanx2)=[tan(a1)+tan(a2)]/(1-
y=1+xe^y两边对x求导得y'=e^y+xe^y*y'(是对x求导那么e^y就是一个复合函数了所以最后要在对y求导)(1-xe^y)y'=e^y∴y'=e^y/(1-xe^y)再问:还不是很明白这
对y求导,e^z*z'(y)=xz+xyz'(y),əz/əy=z'(y)=xz/(e^z-xy)
两边微分e^zdz-yzdx-xzdy-xydz=0(e^z-xy)dz=yzdx+xzdy∂z/∂y=xz/(e^z-xy)=xz/(xyz-xy)=z/(yz-y)
你好:两边同时对x求偏导数(z-x(偏z/偏x))/z2=1/z(偏z/偏x)所以偏z/偏x=z/(x+z)
e^z-z+xy^3=0偏z/偏x:z'e^z-z'+y^3=0y^3=z'(1-e^z)z'=y^3/(1-e^z)偏z/偏y:z'e^z-z'+3xy^2=0z'=3xy^2/(1-e^z)偏z/
两边对x求导得y+xy'=(1+y')/(x+y)y(x+y)+x(x+y)y'=1+y'y'[x(x+y)-1]=1-y(x+y)y'=[1-y(x+y)]/[x(x+y)-1]dy=[1-y(x+
这道题考查隐函数求导方法,求出x=0的倒数就是切线的斜率啦,k1=y‘,然后法线的斜率就是-1/y’.x=0代入方程,得sin0+lny=0即lny=-1解得y=1/e也就是说x=0处曲线上的点是(0
dy=d[tf'(t)-f(t)]=[f'(t)+tf''(t)-f'(t)]dt=tf''(t)dtdx=df'(t)=f''(t)dt所以dy/dx=t
对X的偏导=yz/(e^z-xy)对Y的偏导=xz/(e^z-xy)
dz=-dx-dy
1、2x+2y*dy/dx-y-x*dy/dx=02x-y=(x-2y)dy/dx所以dy/dx=(2x-y)/(x-2y)2、2y*dy/dx-2ay-2ax*dy/dx=0(2y-2ax)dy/d
方程y=sin(x+y)两边对x求导数有:y'=cos(x+y)(x+y)'=cos(x+y)(1+y')移项整理得:[1-cos(x+y)]y'=cos(x+y)因此:y'=cos(x+y)/[1-
对左右两边求导:(1+ez)dz=ydx+xdy.dz=1/(1+ez).(ydx+xdy).