搜狗做题网计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y
计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y
函数y=arctan(1+x^2)求dy/dx
y=arctan(x+1)^1/2,求dy=?
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x^2+y^2=e^(arctan（y/x）),求dy/dx
arctan(y/x)=ln(sqrt(x^2+y^2)),请问dy/dx是什么?
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y=arctan（x^2+1）
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