(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
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(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
详细解题过程,谢谢!
x后面的2是指平方。请高手帮忙解一下,感激不尽!!!
不是解方程,是化简!!!
详细解题过程,谢谢!
x后面的2是指平方。请高手帮忙解一下,感激不尽!!!
不是解方程,是化简!!!
原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)
=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=-(x²-6x+9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=(3-x)/(2x+6)
=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=-(x²-6x+9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=(3-x)/(2x+6)
(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x 化简
化简x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
x · 根号(X2+3X+18) - X · 根号(X2-6X+18)=1 那么2X · 根号(X2-6X+18)-9X
(x-2)(x2-6x-9)-x(x-5)(x-3)其中x= -1/3
(x/x2-9)-(1/x2+6x+9)计算
计算:(1)x2+9xx2+3x+x2−9x2+6x+9
先化解,再求值:【1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)】/1/(x2+9x+20),
已知x2 3x-2=0,求2x-4╱x2 6x 9÷(x-3)×x2-9╱2x-x2的值
先化简,再求值:9x+6x2-3(x-23x2),其中x=-1.
x-3分之x+2乘x2平方-4分之x2平方-6x+9